What coefficients are needed to balance the equation for the complete combustion

Question

What coefficients are needed to balance the equation for the complete combustion of methane? Enter the coefficients in the order CH_4, O_2, cO_2 and H_3 O, respectively. Express your answer as four integers, separated by commas (e.g. 1, 2, 3, 4) What mass of carbon dioxide is produced from the complete combustion of 5.20 times 10^-3 g of methane? Express your answer with the appropriate units. What mass of water is produced from the complete combustion of 5.20 times 10 K of methane? Express your answer with the appropriate units.

Explanation / Answer

Part A:

CH4 + 2 O2 -----> CO2 + 2 H2O

So, the co-effeicients are 1, 2, 1, 2

Part B:

Mass of methane = 5.20 X 10-3 g

Moles of methane = Mass of methane / Molecular mass of methane = (5.20 X 10-3 g) / 16 g/mol = 3.25 X 10-4 mol

Moles of carbon dioxide = Moles of methane = 3.25 X 10-4 mol

Mass of carbon dioxide = Moles of carbon dioxide x Molecular mass of carbon dioxide

= (3.25 X 10-4 mol) X 44 g/mol = 0.0143 g

Mass of carbon dioxide = 0.0143 g

Part C:

Mass of methane = 5.20 X 10-3 g

Moles of methane = Mass of methane / Molecular mass of methane = (5.20 X 10-3 g) / 16 g/mol = 3.25 X 10-4 mol

Moles of water = 2 X Moles of methane = 2 X (3.25 X 10-4 mol) = 6.5 X 10-4 mol

Mass of water = Moles of water x Molecular mass of water

= (6.5 X 10-4 mol) X 18 g/mol = 0.0117 g

Mass of carbon dioxide = 0.0117 g

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