Q1: 46.58KJ of heat is released when 1 mole of HCl reacts with 1 mole of NaOH to

Question

Q1: 46.58KJ of heat is released when 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of H2O. Write a thermochemical equation for this reaction.

Q2: Two 100ml solutions of NaOH and HCl both have a concentration of 1M. When they are mixed in a Styrofoam cup, the temperature raised from 200C to 27.50C. What is the heat released(q)?

Q3: Use the equation to calculate the amount (in moles) of the water produced if you know that the mas of the solution was 100g, the temperature change was 30C, and the specific heat of the solution is 4.084J/0Cg. NaOH(aq) + HCl(aq)NaCl(aq) + H2O + 55.216KJ

Explanation / Answer

Question 1.

The reaction

HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l) HRxn = -46.58 kJ

Question 2.

V = 100 mL = 100 g

total mass = 100+100 = 200 g

dT = 27.5 - 20 = 7.5 °C

Q = m*C*(dT)

Q = 200*4.184*(7.5) = 6276 J = 6.276 kJ released

Question 3.

HRxn = q/n

q = m*C*(Tf-Ti)

q = 100*4.084*(30) = 12252

55216= 12252/moles

molse = 12252/55216 = 0.22189 mol of water

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