Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A problem that asked you to convert molecules to grams could require two steps c

ID: 512131 • Letter: A

Question

A problem that asked you to convert molecules to grams could require two steps convert the molecules to moles convert to moles to grams You learned how to convert molecules to moles in part A. In part C you converted grams to moles, but the same conversion factor inverted would convert moles to grams. You can use these parts to help perform each step. You could also do this in one step by using the conversion factors employed in part A and C to create a new conversion factor that completes the conversion in one step. Sodium hydroxide, NaOH, is a strong base that is used in industrial synthesis and processes such as making paper. What is the mass of 2.90 times 10^22 molecules of NaOH (Molar mass = 400.0 mol)? Express the mass in grams to three significant figures. Ascorbic acid, or vitamin C (C_6H_8O_6, molar mass = 176 g/mol), is a naturally occurring organic compound with antioxidant properties. A healthy adult's daily requirement of vitamin C is 70- 90 mg. A sweet lime contains 2.84 times 10^-4 mol of ascorbic acid. To determine whether the ascorbic acid in a sweet lime meets the daily requirement, calculate the mass of ascorbic acid in 2.84 times 10^-4 mol of ascorbic acid. Express the mass in grams to three significant figures.

Explanation / Answer

Part D:

The "molar mass" of NaOH and the number of molecules of NaOH are given to us

1 mole of NaOH is equal to 40.0g/mol.


First, we have to convert the molecules to atoms using Avogadro's number (=6.02 x 10^23)

(2.90 x 10^22 molecules) / (6.02 x 10^23 atoms) = 0.048 mol

Next, we can convert from moles to grams.

so, 0.048 mol of NaOH x 40.0 g of NaOH/1 mole = 1.92g of NaOH.

There are 1.68 grams in 2.90 x 10^22 molecules of NaOH.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote