How did you calculate the Mole of OH and Molarity of OH and Ca and Ksp, And last

Question

How did you calculate the Mole of OH and Molarity of OH and Ca and Ksp, And lastly pH please help

DATA Concentration of stock HCl solution 0,0400 M Temp of Ca (OH)2 solution 21. le 17. b °C (Boilin C (Room Temp) Trial Trial 1 Trial 1 Trial 2 nitial volume HC 4 z mL. G-34 mL. 3s mL Final volume HC e, mL /l. 22s mL. mL. Trial 3 Trial 3 mL (if necessary) mL (if necessary) Initial volume HCI mL Final volume HC mL CALCULATIONS (Show all work!) Paper 1. Using your experimen data, ete the table below mp mL. Volume HCI used mL mL. mol mo mol Moles HCl mol mol mod s, UMoles Ca(OH)2 2008 mo o 21u mol mo 2+. Moles Ca mol mol mol Moles OH Ca2 [OH Average sp 2. What is the ph of the two saturated Ca (OH)2 solutions?

Explanation / Answer

The substance whose Ph is to be find out = Ca(OH)2

The chemical equation of decomposition of Ca(OH)2

Ca(OH)2 ------------------> Ca ^(+2) +2 (OH) ^ (-)

The "Ksp" expression

Ksp = [Ca ^ +2 ] [OH ^ - ]^2

Use titration data to determine moles of OH^- in the 25 ml of sample .

molarity = number of moles / volume

0.468 moles per milliliter

moles = 0.468 /25 = 0.01872

using the number of moles OH ^- to determine concentrartion of [OH] ^-

0.01872 / 0.025 = 0.7488 mol/L

Using the concentration of [OH] we can determine the concentration of calcium ion , this is because it is in 1:2 molar ratio from the balanced equation

Ksp = [0.01125 ][0.7488] ^2 = 0.0063078912

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