A. The solubility of silver sulfate,Ag2SO4 , in water has been determined to be

Question

A. The solubility of silver sulfate,Ag2SO4 , in water has been determined to be 8.00 g/L. What is the solubility of silver sulfate in 0.350 M of sodium sulfate,NA2SO4 NA2 ?                                            B. Barium sulfate is often used as a test for barium ion in qualitative analysis. Using the solubility product constant (KSP = 1.1X ten to the negative tenth power.    ), calculate the molar solubility of barium sulfate in water                                      C. What is the solubility of magnesium hydroxide in a solution buffered at pH 8.65? KSP = 1.8x ten to the negative 11th power?

Explanation / Answer

A) solubility of AG2SO4 = 8.00g/L

= (8g/302g/mol)/L

= 0.02649 mol

Ag2SO4 --------> 2Ag+ (aq) +SO4-2(aq)

- 2s s

Ksp = (2s)2(s)

= 4s3

= 4 x (0.02649)3

= 7.435 x10-5

Now solubility in Na2SO4

Ag2SO4 --------> 2Ag+ (aq) +SO4-2(aq)

- s 0.35

Ksp = 7.435 x10-5 = (s)2 0.35

Thus s = 0.01457M

The solubility of Ag2SO4 = 1/2 (0.01457) =0.00728

= 7.28x10-3 M

B)

BaSO4 --------> Ba+2(aq) +SO4-2(aq)

- s s

Henc eKsp = s2 = 1.1x10-10

or solubility s = 1.048 x10-5 M

C) pH of buffer = 8.65 that is pOH = 14 -8.65 = 5.35

Thus [OH-] in solution = 4.467 x10-6

Mg(OH)2 (s) ------------> Mg+2 (aq) + 2OH- (aq)

- s 4.467x10-6

Thus ksp = s x  4.467x10-6  = 1.8x10-11

or solubility of Mg(OH)2 = 4.029 x10-6 M

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.