Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A. The decay constant can be found using the equation: Thélé . 06g. . Therefore,

ID: 285833 • Letter: A

Question

A. The decay constant can be found using the equation: Thélé . 06g. . Therefore, = half-life Au half-life 1 pt each Calculate the decay constant Q) for the following isotopes: 238U decay constant 40K decay constant 23U decay constant HC decay constant B. Complete the following table and calculate the time of formation for these samples. Each row is 4 points Rock Sample Isotope | NJNp | NJNP+1 | eru ortion | Tformation Constant equation and/or Mineral Uranite Zircon Mica Volcanic Ash 4K:40Ar Wood K0Ar 14C:HN C. How do these calculated ages compare with the graphical methods you used in this exercise? 2 pts

Explanation / Answer

As per norms I should answer for first question only

1) a) Decay constat for U 238 :

= 0.693/ Halflife of U238

Halflife of U 238 = 1.40805 * 10^ 17 Sec

then, Decay constant = 0.693/ (1.40805*10^17) = 4.916 *10^-18 per Sec

b) Decay constat for U 235 :

= 0.693/ Halflife of U235

Halflife of U 235 = 2.217 * 10^ 16 Sec

then, Decay constant = 0.693/ (2.217 * 10^ 16) = 3.12 *10^-17 per Sec

c) Decay constat for K 40 :

= 0.693/ Halflife of K 40

Halflife of U K 40 = 3.9312 * 10^ 16 Sec

then, Decay constant = 0.693/ (3.9312 * 10^ 16) = 1.762 *10^-17 per Sec

d)

Decay constat for C 14  :

= 0.693/ Halflife of C 14

Halflife of C 14 = 175455000000 Sec

then, Decay constant = 0.693/ (175455000000) = 3.9 *10^-12 per Sec

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote