A geochemist in the field takes a 45.0 mL sample of water from a rock pool lined

Question

A geochemist in the field takes a 45.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X . He notes the temperature of the pool, 29.° C , and caps the sample carefully. Back in the lab, the geochemist filters the sample and then evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.595 g. Do you have enough information to calculate the solubility of X in water at 29.° C? If so, calculate it.

Explanation / Answer

Answer:-

Solubility is the amount of solute dissolved in the solvent at the given temperature .

So, volume of the water sample = 45.0 mL

weight of the crystals = 0.595 g

45.0 mL solution gives = 0.595 g X

Then solubility= 0.595 x 1000/45.0 g/L

= 13.22 g/L

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