we did an experiment to determine the amount of Cl in water by argentometric tit

Question

we did an experiment to determine the amount of Cl in water by argentometric titration
we used 5% K2CrO4 as an indicator 4 drops
and also used 0.1M of sliver nitrate soultion
we added the sliver nitrate to the burette and titrated it in 50ml of water soultion we carried out the experiment three time each with with two different water samples
*for the first water sample the initial burrte reading were 40, 41.2,and 44.4 the final were 41.20, 42.4 and 43.2 the difference or the voulme used 0.lM of silver nitrate was 1.2
* for the second we used distilled water the intial burette reading were 58.2 59.0 and 59.8 final reading were 59.0 59.8 and 60.6
and the voulme used of 0.1M of sliver nitrate was 0.8
the questions are

1. calculate the concentration of AgNo3,Mar
2. calculate your results as the% (w/w)
3. be certain to report each individual value
the mean value, absolute deviation from the mean of each value, the relative average deviation in parts per thousand, the standard deviation and the confidence interval at an appropriate confidence level
thanks .

Explanation / Answer

So, 50mL water contains 2.41 gm Cl-

50mL water = 50gm water

%(W/W) = (2.41/50) *100 % = 4.82 %

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