Gay-Lussac\'s law states that the pressure of a gas is directly related to its a
ID: 507208 • Letter: G
Question
Gay-Lussac's law states that the pressure of a gas is directly related to its absolute temperature, provided the volume and number of moles of the gas remain the same: (Figure 1) P_1/T_1 = P_2/T_2 In an ideal gas, particles are considered to interact only when they collide, with no loss in energy or speed occurring during the collision Studying ideal gases allows for simplifications, such as Gay-Lussac's law. A sample of a gas is in a sealed container. The pressure of the gas is 785 torr, and the temperature is 33 degree C. If the temperature changes to 86 degree C with no change in volume or amount of gas. what is the new pressure. P_2, of the gas inside the container? Express your answer with the appropriate units. Using the same sample of gas (P_1 = 785 torr. T_1 = 33 degree C). we wish to change the pressure to 7850 torr with no accompanying change in volume or amount of gas. What temperature T_2, in Celsius, is needed to reach this pressure? Express your answer with the appropriate units.Explanation / Answer
Part A )
pressure P1 = 785 torr
temperature T1 = 33 + 273 = 306 K
temperature T2 = 86 + 273 = 359 K
P1 / T1 = P2 / T2
785 / 306 = P2 / 359
P2 = 921 torr
new pressure P2 = 921 torr
part B)
pressure P1 = 785 torr
temperature T1 = 33 + 273 = 306 K
pressure P2 = 7850 torr
P1 / T1 = P2 / T2
785 / 306 = 7850 / T2
T2 = 3060
temperature T2 = 3060 K
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