Gauss Law Quick Question A charged sphere of radius R1=0.2 cm and total charge Q

Question

Gauss Law Quick Question

A charged sphere of radius R1=0.2 cm and total charge Q=4.8 nanoCoulomb is placed at the
center of a hollow spherical conducting shell (inner radius R2=1 cm, outer radius R3=2 cm)
which has a net charge Qshell= - 4.0 nanoCoulomb. (See the figure, but note that the figure is not
drawn to scale)
Determine the resulting charge density ? on the inner surface of the conducting spherical shell.
(Give your answer in units of nanoCoulomb / cm2)

DIRECT LINK TO MY IMAGE OR THE FIGURE : http://s30.postimg.org/e02cjgt9t/phyusik.jpg

PLEASE ANSWER THIS AS NEAT AND AS SIMPLE AS POSSIBLE. Hand written = better

Explanation / Answer

The charge on a conducting body can reside only on it' s surface.

Therefore, the charge on the ineer surface=-charge on the solid sphere=-4.8nC

Charge density=Q/Area of inner surface=Q/4pir^2=-(4.8*10^-9)/(4pi*0.01^2)=3.82*10^-6C/m^2

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