What is the activation energy of a reaction if k at 500 K is 2.9 times 10^-1 L/m

Question

What is the activation energy of a reaction if k at 500 K is 2.9 times 10^-1 L/mol middot s and k at 400 K is 6.6 times 10^-4 L/mol middot s? (a) 1.0 times 10^2 J/mol (b) 1.2 times 10^3 J/mol (c) 1.0 times 10^5 J/mol (d) 1.3 times 10^6 J/mol (e) 1.2 times 10^8 J/mol The presence of a non-volatile solute in water will (a) lower the vapor pressure and freezing point and raise the boiling point. (b) lower the freezing point, vapor pressure, and boiling point. (c) lower the freezing point and raise the vapor pressure and boiling point. (d) raise the boiling point, freezing point, and vapor pressure. (e) lower the vapor pressure and boiling point and raise the freezing point.

Explanation / Answer

23)

T1 = 500.0 K

T2 = 400.0 K

K1 = 0.29 L/mol.s

K2 = 6.6E-4 L/mol.s

use:

ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)

ln(6.6E-4/0.29) = ( Ea/8.314)*(1/500.0 - 1/400.0)

-6.09 = (Ea/8.314)*(-5.00E-4)

Ea = 101188 J/mol

   = 1.0E5 J/mol

Answer: c

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