What is the activation energy of the reaction? Express your answer numerically i

Question

What is the activation energy of the reaction?

Express your answer numerically in kilojoules per mole.

The rate constant of a chemical reaction increased from 0.100 s^-1 to 3.30 s^-1 upon raising the temperature from 25.0 degree C to 45.0 degree C Calculate the value of (1/T_2 - 1/T_1) where T_1 is the initial temperature and T_2 is the final temperature. Express your answer numerically. Calculate the value of ln(k_1/k_2) where k_1 and k_2 correspond to the rate constants at the initial and the final temperatures as defined in part A Express your answer numerically.

Explanation / Answer

A)

(1/(45+273)) - 1/(25+273)) = -0.00021

B)

for

ln(K1/K2) --> ln(0.1/3.3) = -3.49650

C)

Finally, apply Ahrrenius equation:

ln(K1/K2) = -E/R* (1/T2-1/T1)

-3.49650 = -E/8.314*(-0.00021)

E =- 3.49650 *8.314 / 0.00021

E = 138428.1 J/mol = 138.428.1 kJ/mol

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