1. Consider the following reaction with energy of activation of + 200kJ: 2A + B
ID: 506277 • Letter: 1
Question
1. Consider the following reaction with energy of activation of + 200kJ:
2A + B --- C + D + 460 kJ. What is the energy of activation of the reverse reaction?
2. Consider the following reaction with energy of activation of - 200kJ:
2A + B --- C + D + (-)460 kJ. What is the energy of activation of the reverse reaction?
3. Consider the following reaction with energy of activation of - 200kJ:
2A + B --- C + D + 460 kJ. What is the energy of activation of the reverse reaction?
Can someone help me figure out how to calculate these? THANK YOU!!!
Explanation / Answer
the equation is:
delta H = Eaf - Eab
delta H : is the heat of reaction
Eaf: is activation energy for forward reaction
Eab: is activation energy of backward reaction
1)
delta H = - 460 KJ as heat is released
delta H = Eaf - Eab
-460 = 200 - Eab
Eab = 660 KJ
Answer: 660 KJ
2)
delta H = 460 KJ as heat is absobed
delta H = Eaf - Eab
460 = -200 - Eab
Eab = -660 KJ
Answer: -660 KJ
3)
delta H = - 460 KJ as heat is released
delta H = Eaf - Eab
-460 = -200 - Eab
Eab = 260 KJ
Answer: 260 KJ
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