1. Consider the following figure. (Let m 1 be the mass of the child, and m 2 be
ID: 1280476 • Letter: 1
Question
1. Consider the following figure. (Let m1 be the mass of the child, and m2 be the mass of the scale.)
(b) What is the mass of the child and basket if a scale reading of 101 N is observed?
____ kg
(c) What is the tension T1 in the cord attaching the child to the scale? (Enter the magnitude only.)
_____ N
(d) What is the tension T2 in the cord attaching the scale to the ceiling, if the scale has a mass of 0.400 kg? (Enter the magnitude only.)
______ N
2. Two blocks each of mass m = 8.50 kg are connected as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? _____ N
Tvertical = 5.87X10^-4
(b) Now, the same spider sits motionless in the middle of a (nearly) horizontal strand of spiderweb, as shown in the figure below. The strand sags at an angle of 10.0 below the horizontal. Calculate the tension in this (nearly) horizontal strand.
Tnew = ???? 1.695X10^-8 DID NOT WORK
1. Consider the following figure. (Let m1 be the mass of the child, and m2 be the mass of the scale.) (b) What is the mass of the child and basket if a scale reading of 101 N is observed? ____ kg (c) What is the tension T1 in the cord attaching the child to the scale? (Enter the magnitude only.) _____ N (d) What is the tension T2 in the cord attaching the scale to the ceiling, if the scale has a mass of 0.400 kg? (Enter the magnitude only.) ______ N 2. Two blocks each of mass m = 8.50 kg are connected as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? _____ N 3. (a) A spider hangs motionless from a single vertical strand of spiderweb. Calculate the tension in the vertical spiderweb if the spider has a mass of 6.00 multiply.gif 10-5 kg. Tvertical = 5.87X10^-4 (b) Now, the same spider sits motionless in the middle of a (nearly) horizontal strand of spiderweb, as shown in the figure below. The strand sags at an angle of 10.0 below the horizontal. Calculate the tension in this (nearly) horizontal strand. Tnew = ???? 1.695X10^-8 DID NOT WORKExplanation / Answer
No 1)
a)mass of child= 101/9.8=10.3kg
b) T1=101N
c) T2=(10.3+0.4)*g=104.92N
No 2)
reading in string=(8.5+8.5)*9.8=166.6N
No 3)
a)T vertical=m*g=5.88*10^(-4)N
b)Figure required
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