The connectivity for PCl_3 is shown in this Lewis symbol figure. Which statement
ID: 506186 • Letter: T
Question
The connectivity for PCl_3 is shown in this Lewis symbol figure. Which statement correctly describes the number of valence electrons to include? Each Cl atom has 7 valence electrons, and the P atom has 5 valence electrons, and so the Lewis structure for PCl_3 will include 26 electrons. Each Cl atom has 6 valence electrons, as does the P atom, and so the Lewis structure for PCl_3 will include 24 electrons. Each Cl atom has 7 valence electrons, and the P atom has 3 valence electrons, and so the Lewis structure for PCl_3 will include 24 electrons. Each Cl atom has 7 valence electrons and so the Lewis structure for PCl_3 will include 21 electrons.Explanation / Answer
Since Chlorine belongs to Gr VIIA of periodic table it possess 7 valence electrons and Phosphorous belongs to Gr VA, and hence contains 5 valence electron.
Thus, each chlorine atom has 7 valence electron and the phosphorous atom has 5 valence electrons
Total valence electrons in PCl3 = (1 x 5) + (3 x 7) = 26 electrons
statement 1 is correct.
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