what is the equilibrium consent value of kc What is the K_c expression for the f

Question

what is the equilibrium consent value of kc What is the K_c expression for the following reaction? 2 NO_2 (g) rightarrowleftarrow 2 NO (g) + O_2 (g) a) K_c = [NO] [O_2]/[NO_2]^2 b) K_c = [2NO]^2 [O_2]/[2NO_2]^2 c) K_c = [NO]^2[O_2]/[NO_2]^2 d) K_c = [NO_2]^2/[O_2][NO] e) K_c = [NO]^2 + [O_2]/[NO_2]^2 Given K_c = 1.6 times 10^-10 for the reaction: 2 SO_3 (g) rightarrowleftarrow 2SO_2 (g) + O_2 (g) Find out K_c for the reaction below: SO_2 (g) + 1/2 O_2 (g) rightarrowleftarrow SO_3 (g) a) 1.3 times 10^-5 b) 6.25 times 10^9 c) 1.6 times 10^-10 d) 7.9 times 10^4 e) 0.80 times 10^-15 What is the equilibrium constant value (K_c) for the following reaction? 2 HI (g) rightarrowleftarrow I_2 (g) + H_2 (g) Given the concentrations of each species at equilibrium are as follows: [HI] = 0.85 M, [I_2] = 0.60 M, and [H_2] = 0.27 M. a) 5.25 b) 0.22 c) 0.45 d) 0.19 e) 1.6 times 10^-2

Explanation / Answer

Ans 1 -Option C is correct

Ans 2 - When the reaction is reversed the kc will change to 1/kc hence option b) is correct

Ans 3 = Option b) is correct as the equribrium constant is-

Kc =[0.60][0.27] / [.85]2  

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