Molar mass of acid? Avg molar mass of acid Percentage error? **Identity not need

Question

Molar mass of acid? Avg molar mass of acid Percentage error? **Identity not needed** Please help me complete.
NB: the molar masses of the unknowns are (g/mole) 126.07, 134.08, or 150.09. Remember they are all diprotic acids. It is not necessary to name the unknown acid. DATA SHEET Part B: Molar Mass of an Unknown Acid Code Number of Unknown Acid IRIAL1 IREAL2 IRLAL3 IRIAL4 IRIALS 25 Mass Acid a o 2. Molarity of NaoH used ou Initial Buret Vol. (v) So -24 Final Buret Vol. (V) Vol. of NaOH used AV a V-V Molar Mass of Acid Show a sample calculation: Average Molar Mass of Acid (using best three trials) Identity of Acid (from list of possible unknowns) Percent Error Show Calculation: Name Lab Day M T w R F Instructor Room: 103 109 117 125 Lab Time

Explanation / Answer

Follow this procedure,
Number of moles of unknown acid = Number of moles of NaOH = molarity of NaOH*Volume of NaOH
After getting number of moles of unknown acid as above,
moles of unknown acid = Mass of acid in gm / Molar mass
From the above equation we get the molar mass of the acid.
Take the average of all the four trials
For the percent error you need to identify the Unknown acid by its molar mass (average value),
% error = [ | original mass - avg molar mass| / avg molar mass ] * 100

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