4. General Instructions for the following problems instructor might give additio
ID: 499258 • Letter: 4
Question
4. General Instructions for the following problems instructor might give additional spectrum list problem contains some combination of the following information: IR UV peak, (with of absorption frequencies), mass spectrum or molecular major element on each IR neatly label the major peaks with the structural fragment which causes the absorption. Use the back of the page for calculation of molecular for notes, and the answer. DO NOT use the problem area for scratch work. Draw an expanded structural formula for the identified compound. Name the compound. For 2 of the six problems, attach a copy of a published reference IR spectrum (either from an on-line or hard copy source) with all the major absorption peaks clearly marked. (Make sure that you do not submit a gas-phase spectrum if the problem set shows a liquid or solution- phase spectrum.) Give proper citations to the source of the spectra. Consult the lab manual, the lab textbook by Pavia, et al., and the lecture textbook to help you with the analyses.
Explanation / Answer
To solve this type of problem
We need to have molecular formula
But no worries
We can calculate it from mass
Lets see example b)
M+ is 73
According to rule of 13
We should divide m+ by 13
73/13=5 (8)
5+8=13
So we can say we have 5 carbons and
13 hydrogen
But IR peak at 3297 shows that it may contain NH or OH
So previously out formula was C5H13
If we add N we need to substract it's equivalent CH2
So formula will be C4H9N
As there is one site of unsaturation
So it may ring or double bond
IR shows 3297 will be NH
And 2900 Shows CH
1080-1360 CN streaching
1600 will be NH Bending
So we answer is tetrahydropyrol
Give membered saturated ring with NH
So we can say that it is
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