The equilibrium constant for the chemical equation is Kp = 0.0128 at 245 °C. Cal

Question

The equilibrium constant for the chemical equation is Kp = 0.0128 at 245 °C. Calculate the value of the Kc for the reaction at 245 °C.

112017 10.00 PM GO 7.3/10 G 3/21/201708:57 PM Print Calculator Periodic Table ion 9 of 19 eneral Chemistry 4th Editon University Science Books presented by Sapling Learning The equilibrium constant for the chemical equation N,(g) 3H,(g 2NH is Kp* 0.0128 at 245 C. Calculate the value of the Ko for the reaction at 245 "C. Number Hint O Previous Give Up & View Solution 2 Check Answer Next

Explanation / Answer

T = 245.0 oC =(245.0 + 273) K= 518.0 K

delta n = number of gaseous molecule in product - number of gaseous molecule in reactant
delta n = -2

Kp= Kc (RT)^delta n
0.0128 = Kc *(0.0821*518.0)^(-2)
Kc = 23.1503

Answer: 23.15

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