Are the following statements True (T) or False (F)? Circle the correct answer. D

Question

Are the following statements True (T) or False (F)? Circle the correct answer. D-Glucose and L-glucose are Isomers (T/F) D-Glucose and L-glucose are Enantiomers (T/F) D-Glucose and L-glucose are Diasteriomers (T/F) D-Glucose and L-glucose are Epimers (T/F) How does the cyclization of a monosaccharide introduce a new chiral center? Illustrate your answer with D-Glucose. Amylose and cellulose are both composed of D-glucose units with a 1-4 linkage. However, amylose is readily digested by animals whereas cellulose is not. What difference in the two polymers account for this? What is a Pyranose? How is it different from a Furanose? How are keto pentoses different from aldo pentoses?

Explanation / Answer

Question 1.

i. true

ii. true

iii. false

iv, true

Glucose can form 16 isomers b/c it has 4 asymmetric carbons:
1)D & L isomers
2)Pyranose & Furanose Ring Structures
3) and anomers
4)Epimers
5)Aldose & Ketose Isomerism

Two carbohydrates (D Glucose    AND L Glucose). THEY are said to be enantiomers on the off chance that they are nonsuperimposable identical representations of each other. A case of an enantiomer is the D and L isomers of glucose, as appeared by the figure to one side.

A moment sort of isomer found in starches are diastereoisomers. Sugars are delegated diastereomers if their chiral carbons are associated with the very same substrates however associated at varying designs (R or S). Not at all like an enantiomer, diastereomers are NOT question and identical representation. A case of two sugars that are diastereoisomers are D-Glucose and D-Altrose as found in the figure to one side.

In conclusion, another sort of isomer that carhbohydrates that can thought on are epimers. Epimers are two diastereomers that contrast just at one stereocenter.[1] As appeared in the figure beneath, D-Glucose and D-Mannose are a case of an epime

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2 .How does the cyclization of a monosaccharide introduce a new chiral centre

>The formation of a new stereoisomesr due to the cyclization of monosaccharides, which changes the former carbonyl C atom into a NEW CHIRAL CENTER
-->Cyclization of a monosaccharide will produce 2 major ENANTIOMERS of an anomeric carbon:
1) -Anomer: Contains the -OH group ABOVE the plane of the ring on the anomeric carbon
2)-Anomer: Contains the -OH group BELOW the plane of the ring on the anomeric carbon

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