The enzyme-catalyzed conversion of a substrate at 25C has a Michaelis constant o

Question

The enzyme-catalyzed conversion of a substrate at 25C has a Michaelis constant of 0.034 mol L-1 . The rate of the reaction is 8.64 x 10-3 mol L-1 s -1 when the substrate concentration is 0.290 mol L-1 . What is the maximum velocity of this enzymolysis?

5. 6. The enzyme-catalyzed conversion of a substrate at 250C has a Michaelis constant of 0.034 mol L 1. The rate of the reaction is 8.64 x 10 3 mol LT s when the substrate concentration is 0.290 mol L What is the maximum velocity of this enzymolysis?

Explanation / Answer

. What is the maximum velocity of this enzymolysis?

Dp/dt =K[E]

K=Kb[S] /Km +[S]

V= Kb[S] [E]/Km +[S]

Kb[S] ([E] =(Km +[S] /[S] r

=(0.034+0.290/0.290) *8.64 x 10^-3

=9.652 X10^-3

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.