P_1V_1 = P_2V_2 Standard Pressure: 1 atm. 101.3 kPa, 760 mm Hg. 760 Torr, 14.7 I
ID: 497200 • Letter: P
Question
P_1V_1 = P_2V_2 Standard Pressure: 1 atm. 101.3 kPa, 760 mm Hg. 760 Torr, 14.7 Ib/in^2 1. If a sample of gas has a volume of 310 mL when the pressure is 150 kPa, what will the volume be of the gas if its pressure is increased to 200 kPa? 2. A sample of gas has a volume of 460 mL when the pressure is 1.45 atm. What is its volume when the pressure is 190 mm Hg? 3. A gas occupies a volume of 270 mL at 560 mm Hg pressure. To what pressure must the gas be subjected in order to change the volume to 75.0 mL? 4. A given mass of hydrogen gas occupies 41.0 L at 161.95 kPa pressure. What volume will it occupy at 5.12 atm pressure? 5. What pressure would be required to compress 2500 Lof a gas at 100 atm to a volume of 35.5 L? Express your answer in kPa.Explanation / Answer
1. According to Boyle law at constant temperature
P1V1=P2V2
Given P1=150kpa, V1=310ml
P2=200kpa, V2=?
Putting values in above equation
V2=232.5 ml
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.