P_1 V_1/T_1 = P_2V_2/T_2 PV = nRT M = mRT/PV R = 0.08206 L-atm/mol.K A teaching

Question

P_1 V_1/T_1 = P_2V_2/T_2 PV = nRT M = mRT/PV R = 0.08206 L-atm/mol.K A teaching assistant was determining the molar volume of nitrogen gas, N_2(g). (MW: 28.013 g/moL), at standard temperature and pressure. The TA found that 158 ml of gas was collected at 21.0 degree C and 0.988 atm. The TA determined the volume of this gas sample at STP (1.00 atm and 273 K) is____ mL. Your answer should be expressed with the correct number of significant figures. DO NOT include units. Another TA was working on determining the mollar volume of nitrogen gas. This TA found the volume of a 0.215 g sample of N_2(g) (MM = 28.0134 g/mo) to be 171 mL at STP. The experimental molar volume of this gas is _____L/mol. Your answer should be expressed with the appropriate number of significant figures. DO NOT include units.

Explanation / Answer

P1 = 0.988 atm, V1 = 158 mL, T1 = 294 K , P2 = 1 atm, T2 = 273 K

Using eqn P1V1/T1 = P2V2/T2 and putting values we get :
V2 = 144.953 mL

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Moles of gas in the sample = mass / MW = 0.215 / 28.0134 = 0.00767 moles

Volume occupied = 0.171 L

Thus total volume that will be occupied by 1 mole gas = 0.171 / 0.00767 = 22.294 L

Thus molar volume = 22.294 L/mol

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