question 43 and 44 Write a balanced chemical equation for the reaction of aqueou

Question

question 43 and 44

Write a balanced chemical equation for the reaction of aqueous solutions of (NH_4)_2SO_4(aq) + 2 NaOH(aq) rightarrow 2 NH_4OH(aq) + SO_3(g) + Na_2O(aq) (NH_3)_2SO_4(aq) + NaOH(aq) rightarrow 2 NH_3(g) + NaOHSO_4(aq) (NH_3)_2 SO_4(aq) + 2 NaOH(aq) rightarrow 2 NH_3(g) + Na_2SO_4(aq) + 2OH-(aq) (NH_4)_2SO_4(aq) + 2 NAOH(aq) rightarrow 2 NH^+_4 (g) + NaSO_4(aq) + 2 OH-(aq) (NH_4)_2SO_4(aq) + 2 NaOH(aq) rightarrow 2 NH_3(g) + 2 H_2O(l) + Na_2SO_4(aq) The net ionic equation for the reaction of calcium sulfite with nitric acid is CaSO_3(s) + 2H^+(aq) rightarrow Ca^2+ (aq) + SO_2(g) + H_2O(l). Ca^2+(aq) + CO^2-_3(aq) + 2H^+(aq) + 2NO^-(aq) rightarrow Ca(NO_3)_2(aq) + SO_2(g) + H_2O(l). CaSO_3(s) + 2HNO_2(aq) rightarrow Ca^2+(aq) + 2NO^-_2(aq) + SO_2(G) + H_2O(l). Ca(HSO_3)_2(s) + 2HNO_3(aq) rightarrow Ca^2+(aq) + 2NO^-_3(aq) + SO_2(g) + 2H_2O(l). CaSO_3(s) + 2HNO_3(aq) rightarrow Ca^2+(aq) + 2NO^-_3(aq) + SO_2(g) + H_2O(l). The oxidation number of chlorine is highest in

Explanation / Answer

Q43

ammonium sulfate + sodium hydroxide:

(NH4)2(SO4) + Na(OH)

note that:

NaOH is strong base and NH4+ is a weak acid:

NH4+ + OH- --> NH3 + H2O

so, NH# gas and H2O liquid forms, NA2SO4 remains in ionic

the ratio is:1:2 so:

2 mol of NH3 form:

ignore a, d,

2 mol of H2O form, ignore all

then, only E is true

Q44

net ionic equation contains only ions reacitng so

calcium sulfite --> CaSO3 and nitric acid --> HNO3

the overall reaction:

CaSO3 + 2 HNO3 = Ca(NO3)2 + H2O + SO2

so...

ignore b and d, since those reactants states of Calcium are not correct

ignore a, since 2H+ is not nitric acid

so only c and e can be

c can't be since NO2- is present this s nitrous acid, so

choose

E

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