question 42 Chapter 9 A laboratory tested 57 chicken eggs and found that the mea
ID: 3321834 • Letter: Q
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question 42
Chapter 9 A laboratory tested 57 chicken eggs and found that the mean am ta 95% confiden milligrams with the standard deviation 18.4 milligrams. for the true mean cholesterol content of all such eggs mount of cholesterol was 200 he mean a Construct a 95% confidence interval 42. A Gallup poll conducted in November 2010 found that 493 it is the responsibility of the federal government to mak coverage of 1050 adult Americans believes e sure all Americans have healthcare a) Construct a 95% confidence interval for the proportion of adu lt Americans who believe it is the responsibility of the federal government to make sure all Amenc coverage. b) Construct a 99% confidence interval for the proportion of adult Americans is the responsibility of the federal ment to make sure all Americans healthcare govern coverage. 43. A random sample of 51 fatal crashes in 2009 in which the driver had a positive blood a concentration (BAC) from the National Highway Traffic Safety Administration result mean BAC of 0.167 grams per deciliter (g/dL) with a sample standard deviation of o gdL. Determine and interpret a 90% confidence interval for the mean BAC in fatal which the driver had a positive BAC. . Nielson Media research wants to estimate the mean amount of time (in minutes) college students spend watching television each weekday. Find the sample siz confid estimate that mean with 15-minutes margin of error. Assume that 96% desired. Also assum e that the population standard deviation is 112.2 minutesExplanation / Answer
Solution:- Given that n = 1050 , x = 493
=> p = x/n = 493/1050 = 0.4695 q = 1 - p = 0.5305
a) 95% confidence interval :- p +/- Z*sqrt(pq/n)
95% confidence interval Z = 1.96
=> 0.4695 +/- 1.96*sqrt(0.4695*0.5305/1050)
= (0.4393 , 0.4997)
b) 99% confidence interval :- p +/- Z*sqrt(pq/n)
99% confidence interval Z = 2.575
=> 0.4695 +/- 2.575*sqrt(0.4695*0.5305/1050)
= (0.4298 , 0.5092)
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