Stoichiometry! Remember your steps. Get to moles Use the balanced reaction to co

Question

Stoichiometry! Remember your steps. Get to moles Use the balanced reaction to convert from moles of what you have to moles of what you want Convert to the final unit the question asks for Baking soda, NaHCO_3, is used in baking because it can decompose to produce carbon dioxide gas and the gas bubbles make baked goods rise. The equation for the reaction is: 2NaHCO_3(s) + heat rightarrow Na_2CO_3(s)+CO_2(g) + H_2O(g) a) If 84.0 g of baking soda reacts, how many grams of carbon dioxide are produced? b) If 1.0 g of baking soda react, how many grams of carbon dioxide are produced? c) If you end this reaction with 5.0 g of Sodium Carbonate, Na_2CO_3, how many grams of baking soda did you have to start with?

Explanation / Answer

Q4.

m = 84 g of NaHCO3 (baking soda) find mol of CO2 produced

so... Molar mass of NaHCO3 = 84.007 g/mol

mol = mass/MW = 84/84.007 = 1 mol of baking soda

so

from the reaction, 2 mol of NaHCO3 --> 1 mol of CO2

so

1 mol --> 1/2 mol of CO2, that is 0.5 mol of CO2

mass of CO2 = mol*MW = 0.5*44 = 22 g of CO2

b)

for, 1 g of baking soda..

we can now relate:

84 grams of NaHCO3 --> 22 g of CO2

then

1 g of NaHCO3 --> ? x of CO2

relate x --> 22/84 * 1 = 0.26190 g of CO2

c)

m = 5 g of Na2CO3, find grams of baking soda

mol of Na2CO3 --> Mass/MW = 5/105.98844 = 0.047174 mol of Na2C#

so...

ratio is also 2:1

2 mol --> 1

0.047174 mol --> 2*0.047174 = 0.094348 mol of NaHCO3

mass = mol*MW = 0.094348*84 = 7.925232 were required

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