In a high-pressure separation process, a gas having a mass composition of 50% be

Question

In a high-pressure separation process, a gas having a mass composition of 50% benzene (C6H6), 30% toluene (C7H8), and 20% xylene (C8H10) is fed into the process at a rate of 483 m3 /h at 607 K and 26.8 atm. One exit stream is a vapor with a mole composition of 91.2% benzene, 7.2% toluene, and 1.6% xylene. A second exit stream is liquid with a mass composition 6.0% benzene, 9.0% toluene, and 85.0% xylene.

What is the composition of the third exit stream if it is liquid flowing at a rate of 9800 kg/h, and the ratio of benzene to xylene in the stream is 3 kg benzene to 2kg xylene?

C6H6: MW = 78, Tc = 562.6 K, pc = 48.6 atm
C7H8: MW = 92, Tc = 593.9 K, pc =40.3 atm
C8H10: MW = 106, Tc = 619 K, pc = 34.6 atm

Explanation / Answer

Dear Student,

In a high-pressure separation process, a gas having a mass composition of 50% benzene (C6H6), 30% toluene (C7H8), and 20% xylene (C8H10) is fed into the process at a rate of 483 m3 /h at 607 K and 26.8 atm. One exit stream is a vapor with a mole composition of 91.2% benzene, 7.2% toluene, and 1.6% xylene. A second exit stream is liquid with a mass composition 6.0% benzene, 9.0% toluene, and 85.0% xylene.

the composition of the third exit stream if it is liquid flowing at a rate of 9800 kg/h, and the ratio of benzene to xylene in the stream is 3 kg benzene to 2kg xylene

therefore benzene 45% toluene 30% xylene 25%

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.