In a high-energy physics experiment, a subnuclear particlemoves in a circular ar

Question

In a high-energy physics experiment, a subnuclear particlemoves in a circular arc of 2.71 m radius perpendicular to amagnetic field of 2.70×10-2 T. The kinetic energyof the particle is determined to be 4.09×10-14 J.Identify the particle from its mass. The masses of the positron,pion, kaon, proton, muon and Dmeson are 9.10×10-31kg, 2.50×10-28 kg, 8.84×10-28 kg,1.67×10-27 kg, 1.88×10-28 kg and3.35×10-27 kg, respectively. Assume that theparticle is known to have a positive charge equal to the magnitudeof the electron charge. Enter the name of the particle from thelist given above. What on earth am I supposed to do here? ANY help please:) In a high-energy physics experiment, a subnuclear particlemoves in a circular arc of 2.71 m radius perpendicular to amagnetic field of 2.70×10-2 T. The kinetic energyof the particle is determined to be 4.09×10-14 J.Identify the particle from its mass. The masses of the positron,pion, kaon, proton, muon and Dmeson are 9.10×10-31kg, 2.50×10-28 kg, 8.84×10-28 kg,1.67×10-27 kg, 1.88×10-28 kg and3.35×10-27 kg, respectively. Assume that theparticle is known to have a positive charge equal to the magnitudeof the electron charge. Enter the name of the particle from thelist given above. What on earth am I supposed to do here? ANY help please:)

Explanation / Answer

the velocity of the particle is perpendicular to vector B thus, q*v*B=m*v2/r ;kinetic energy=K=m*v2/2 => v=(2K/m) ; q*v=2K/rB=1.12*10-12=>v=6.99*106 m/s and r=mv/qB =>m=r*q*B/v =1.67*10-27 kg which is a proton.

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