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Print out the graphical data and look at each graph to test for the orders: Zero

ID: 493870 • Letter: P

Question

Print out the graphical data and look at each graph to test for the orders: Zero: [A] vs. time First InlAl vs. time Second 1 [A] vs. time Third 1 20Al vs. time The graphs are presented in the previous order (Zero, First, Second, and Third) from top to bottom. Data Table 1, graphs are presented first followed by Data Table 2 graphs. The linear equation and the Ra factor are included on the plots. The R factor is measure of the linear quality of the line. A perfect line has R2 1.000000. As the linear quality decreases, so does the R factor. Find the linear graph with the highest R2 value...that is the order. You must choose which graphs are "most" linear for each reactant Ioland [Hsol. This gives the order for that reactant. Compare these orders to those predicted by the Mechanism below. Answer the questions that follow. Proposed Mechanism for the Iodine Clock Reaction ementary MI loi 3Hsoh I. 3 SO 3 H SLOWEST FAST Elementary H2 IO 5 I- 6 H 3 l2 3 H20 Elementary #3 Hso, H20 2 soe 3H FAST 1. write out the overall reaction under study.

Explanation / Answer

Q1. OVerall reaction under study:

Add elementary reactions:

IO3- + 3HSO3- = I- + 3SO4-2 + 3H+

IO3- + 5I- + 6H+ = 3I2 + 3H2O

I2 + HSO3- + H2O = 2I- + SO4-2 + 3H+

IO3- + 3HSO3- + IO3- + 5I- + 6H+ + I2 + HSO3- + H2O =  I- + 3SO4-2 + 3H+ + 3I2 + 3H2O +  2I- + SO4-2 + 3H+

cancel common terms

4HSO3- + 2IO3- + 2I- = 4SO4-2+ 2I2 + 2H2O

Q2.

for the rate law, we choose the slow step since those will determine the rte

IO3- + 3HSO3- = I- + 3SO4-2 + 3H+

choose only reactants

RAte = k[IO3-][HSO3-]^3

Q3.

from the graph:

This is second order, since 1/C vs . time is the best fit

so

RAte = K[HSO3-]^2

Q4.

This does not support our previous theory stated in 3,

this is most likely due to the fact that we are only comparing to ONE reactant, we need to compare two reactants

this is best done using the Initial Rates Method

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