Data: 2SO_2 (g) + O_2 (g) rightarrow 2SO_3 (g) Delta H degree = -198 kJ Use the
ID: 493643 • Letter: D
Question
Data: 2SO_2 (g) + O_2 (g) rightarrow 2SO_3 (g) Delta H degree = -198 kJ Use the data above to calculate the standard enthalpy change for the reaction below. Reaction: 2SO_3(g) rightarrow O_2(g) + 2SO_2(g) Delta H degree = ? Miss Louise Washington is on diet program. Her doctor indicated she can only uptake fewer than 8 calories. She did a combustion reaction of a serving double layered chocolate cake. The temperature increased from 24.15 degree C to 29.89. Did she follow- the doctor's order? (C = 8.515 kJ/K, q = C times Delta T) Does Miss Washington follow the doctor's order?Explanation / Answer
1.
reversing a reaction just reverses the sign of S,H or G
so,
Ho for new reaction will be 198 KJ
Answer: 198 KJ
3.
Temperature change = 29.89 - 24.15 =5.74 oC = 5.74 k
q = C*temperature change
= 8.515 KJ/K * 5.74 K
=48.88 KJ
= 48.88/4.184 Kcal
= 11.7 Kcal
This is more than 8 cal.
No, she didn't follow the doctor's order
I am allowed to answer only 1 question at a time
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