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PLEASE ANSWER E ! Analysis is one of the many things chemists do. In this experi

ID: 490698 • Letter: P

Question


PLEASE ANSWER E ! Analysis is one of the many things chemists do. In this experiment, you will analyze a sample for its Hydrogen Peroxide content. To do this you will use three different methods. Titration with Potassium Permanganate Catalytic Decomposition to Water and Oxygen Oxidation of Iodide to Iodine; Spectroscopic measurement of Triiodide ion. You weigh out Potassium Permanganate. Mass of KMnO_4 (MW=158.034) 0.1927 g You dissolve it completely in water 41.00 ml Molarity of MntO_4 solution You pipette out your UNKNOWN 1.10 ml. You acidify and titrate it with your KMnO_4 solution until the permanganate color persists. Volume of permanganate solution 15 .68 ml. Molarity of the HOOH in the UNKNOWN You pipit your UNKNOWN into a reaction tube 4.20 ml. Add a "boat" containing Manganese Dioxide. MnO_2 Set up the gas collection apparatus shown on the right. You sink the boat and allow the oxygen generated to collect in the collection flask. The water temperature is 22 degree C the Barometric Pressure is 771.8 mm Hg Weight of the collection Flask with remaining water 221.25 g. Weight of collection flask filled with water 272.38 g. Density 0.9% g/cc Partial Pressure of Oxygen collected mm Hg Volume of oxygen collected Millimoles of oxygen gas generated mmol Molarity of Hydrogen Peroxide in UNKNOWN M Pull into a clean 250 mL volumetric flask exactly 0.90 ml of 0.90 mM iodate STANDARD. Add an excess of 1M K1 and 1M Sulfuric Acid and let stand for 5 minutes. Dilute low volume. Pipet into a clean 250 ml. volumetric flask 1.00 ml. of your UNKNOWN and dilute to volume with distilled water. Pull into a clean 250 ml. volumetric flask exactly 0.90 mL

Explanation / Answer

from gas law equation, PV=nRT

n= PV/RT, P= 751.973/760 atm =0.989 atm, V = 51.33ml (1000ml= 1L) hence 51.33/1000 L= 0.05133L

R= 0.0821 L.atm/mole.K T= 22 deg.c =22+273= 295K

n= 0.989* 0.05133/(0.0821*298)= 0.002075 moles = 0.002075*1000millimoles = 2.075 mill moles

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