Two different proteins X and Y are dissolved in aqueous solution at 37 C. The pr

Question

Two different proteins X and Y are dissolved in aqueous solution at 37 C. The proteins bind in a 1:1 ratio to form XY . A solution that in initially 1.00 mM in each protein is allowed to reach equilibrium , 0.18 mM of free X and 0.18 of mM of free y remain Masteringchemis C Secure https://session.masteringchemistry.com/myct/itemview?assignmentProblemID-80101057 CHM 114 HW WOLF Spring 2017 Problem 15.39 Problem 15.39 Part A Two different proteins X and Y are dissolved in aqueous What is K for the reaction? solution at 37°C The proteins bind in a 1:1 ratio to form Express your answer using two significant figures. XY, A solution that is initially 1.00 mM in each protein is allowed to reach equilibrium. At equilibrium, 0.18 mM of free X and 0.18 mM of free Y remain. Ke 0.20, 0.80 Submit Incorrect: Try Again class search/co x M

Explanation / Answer

The protein binding reaction in equilibrium is

---------------- X + Y <------> XY

Initl.con(mM): 1.00, 1.00, ------ 0

change(mM): - y , - y -------- +y

eq.con(mM):(1.00 - y), (1.00 - y), y

Given at equilibrium, (1.00 - y) = 0.18 mM

=> y = 1.00 - 0.18 = 0.82 mM

Hence [XY]eq = 0.82 mM

[X]eq = [Y]eq = 0.18 mM

Kc = [XY]eq / ([X]eq*[Y]eq)

=> Kc = 0.82 mM / (0.18 mM*0.18mM) = 25 (answer)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.