Hi, need help with this question. In maize, the recessive genes su and sh (when

Question

Hi, need help with this question.

In maize, the recessive genes su and sh (when homozygous) produce sugary and shrunken endosperm, respectively. Their dominant alleles Su and Sh produce normal starchy and full endosperm. A true breeding sugary variety is crossed to a true breeding shrunken variety and the F1 progeny are all starchy and full. The F1 generation is crossed to a sugary & shrunken variety (su su and sh sh) and produce 1000 progeny in the following numbers: 160 starchy/full, 350 sugary/full, 340 starchy/shrunken and 150 sugary/shrunken plants. The NULL Hypothesis = “The progeny classes are in equivalent numbers”. SHOW ALL WORK!

i) Use the chi-square analysis to evaluate your hypothesis? (8 pts)

ii) Do you reject or fail to reject the NULL hypothesis (at the 0.05 level)? What does this mean? (2 pt)

I am just confused on how to determine the expected ratios for the F2 generation?

Explanation / Answer

(i) null hypothesis is rejected that all the progeny classes are in equivalent numbers. because in F2 the ration of progeny classes would be 1:2:1 and not equivalent. the observed ratio is- 0.16: 0.69 : 0.15 which is not significantly fit to 1: 2:1

(ii) 160 SU SS , 350su SS, 340SU ss , 150 su ss. null hypothesis is rejected at 0.05 level

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