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llsshment takellaunch jsp?course assessment idre 662143 18course id .340851.18co

ID: 488078 • Letter: L

Question

llsshment takellaunch jsp?course assessment idre 662143 18course id .340851.18content id-1540966a QUESTION 35 Which ofthe following solutions has the highest concentration oftoHr A solution with an H30 nof1*1013M B A solution with an H3ohof68 10 s M o C. A solution with a PHof10 D. A solution with an toHnof1 x 10 2M 0 E A solution with a pH of4 QUESTION 36 s the ketone oxidized or reduced during this reaction and how can you tell? o A. Neither This is not an ox reduction reaction idation B. The ketone is reduced because it loses two hydrogens c The ketone is oxidized because it hydrogens D. The ketone is reduced because it gains two hydrogens an oxidation-eduction reaction E The is both oxidized and reduced because this is ketone QUESTION 37 at to of ale obol can wederro which classification i A Only secoedary alcohol ox dited B. Only tertiary alcoboli produce tetoets wt oxidized C Both secondary and tertiary alcobol peodite Eetones D Both primary and secondary l E Only primary alcohols produce QUESTION 38 following choices soMETIMEs occur during a reduction? gain of loss of electrons

Explanation / Answer

SOLUTION:

NOTE: Dear candidate you have asked too many questions. As per guidelines one question is to be solved one time. Here we solve first FIVE questions. Please send others separately.

Q35. OPTION (A) IS CORRECT ANSWER. It can be solved as:

[H+][OH-] = KW = 1 X 10-14

In Option (A) [H+] = 1 X 10-13

[OH-] = 10-14/10-13 = 1 X 10-1

When pH is 10 the H+ concentration is given as:

pH = -log[H+]

[H+] = 10-pH = 10-10

therefore [OH-] = 10-14/10-10 = 1 X 10-4

When pH = 4; [H+] = 10-4, [OH] = 10-10

Q36. OPTION (D) IS CORRECT ANSWER. Gain od hudrogen is redction. The Ketone gains two electrons.

Q37. OPTION (A) IS CORRECT ANSWER. Secondary alcohols produce ketones, primary alcohols produce aldehydes and tertiary alcohols are resistant to oxidation.

Q38. Both option (A) and (B) are correct. As per the demand of question most approptriate is OPTION (A).

Q31. OPTION (B) IS CORRECT ANSWER. Increase in temperature increase the fraction of molecules having sufficient energy to react.