lle Edit View History Bookmarks Window Help 58% Sun 8:13PM , HW 28a 0 2. - point

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lle Edit View History Bookmarks Window Help 58% Sun 8:13PM , HW 28a 0 2. - points An alpha particle travels at a velocity of magnitude 480 m/s through a uniform magnetic field magniude085 T. (An alipha particle hes a charge of +3.2 x 10 and a mass of 6.6 × 10-27 kg.) The angle between and is 6 C (a) what is the magnitude of the force Fs acting on the particle due to the field? (b) What is the magnitude of the acceleration of the particle due to FB? m/s2 (c) Does the speed of the particle increase, decrease, or remain equal to 480 m/s? remains the same A proton moves through a uniform magnetic field given by -(101-23.6 j+30 K) mT. At time ty, the proton has a velocity given by -vxitvy j (2000 mv's) k and the magnetic force on the proton is Fo (4.38 x1017 N)i+(1.86 x 10-17 N) 3. O-1 point (a) At that instant, what is v,? m/s

Explanation / Answer

Only one question can be posted as per chegg guidelines

2.

a)

Magetic force is given by

F=qVBSin(o)=(3.2*10-19)*(480)*0.085*sin68

F=1.21*10-17 N

b)

acceleration of the particle is

a=F/m =(1.21*10-17)/(6.6*10-27)

a=1.834*109 m/s2

c)

remains the same

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