A chemist lot gets to initially dry a test tube to constant mass before dehydrat

Question

A chemist lot gets to initially dry a test tube to constant mass before dehydrating an unknown metal sulfate hydrate (assume the remainder of the experiment is performed properly) As a result, will the mass percentage (%) of water in the sample be overestimated, underestimated or remain unaffected? Explain your reasoning. A chemist heats an unknown metal sulfate hydrate too vigorously in the dehydration process, and us a result, some of the solid in the test tube is ejected onto the lab bench. If this loss is not considered, will the calculated mass percentage (%) of water in the sample be overestimated, underestimated or remain unaffected? Explain your reasoning.

Explanation / Answer

1) if the chemist didn't dry the tube before taking mass of the tube water molecule present in the tube will also be added to the intial mass of the tube.but final mass of tube will remain same as all the water will be evaporated. mass of water = intial mass of tube - final mass of tube

if intial mass of tube increases but final mass remains same we will calculate as there is more ware molecule and hence we will overestimate the mass % of water in sample.

2) if some of the solid is ejected then it will reduce the final mass of the tube will reduce thereby increasing the mass of water estimated.

it will lead to overestimation of mass % of water in sample

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