Given the following chemical equation below 3 As_2O_3 + 4 NO_3^- + 7 H_2O + 4 H^

Question

Given the following chemical equation below 3 As_2O_3 + 4 NO_3^- + 7 H_2O + 4 H^+ rightarrow 6 H_3AsO_4 + 4 NO Assign oxidation numbers (oxidation state) to each atom in the chemical equation, writing the oxidation number below each atom. Using the assigned oxidation numbers IP Part "a", identify the atom undergoing oxidation Explain how you arrived at your answer. You will only receive credit for your answer if you Mate the starting oxidation of the atom you chose and the oxidation number it changed to.

Explanation / Answer

Ans (a)

3 As2 O3   + 4 N O3- + 7 H2 O + 4 H + ___> 6 H3   As   O4 + 4 N O

+3 -2 +5 -2 +1 +5 -2 +2 -2 Oxidation Number

Now,

1] Oxidation Reaction,

As2O3 ______> H3AsO4

Balancing the oxidation reaction equation,

As2O3 + 5 H2O ______> 2 H3AsO4 + 4H + + 4e - ......................... equation 1

2] Reduction Reaction

NO3- ______> NO

Balancing the reduction Reaction

N O 3 - + 4 H + + 3 e - ______> N O + 2 H 2 O ......................... equation 2

Now ,

Multiplying the equation 1 by 3 , and equation 2 by 4 , as equalising the electrons on both the sides....

we get,

3 As2 O3 + 15 H2 O _______> 6 H3 As O4 + 12 H + + 12 e - ............... equation 3

4 NO3- + 16 H + + 12 e -  ________> 4 N O + 8 H2 O ......................equation 4

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We get,

3 As2O3   + 4 NO3- + 7 H2O + 4 H + ___> 6 H3AsO4 + 4 NO

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Ans (b)

The atom undergoing oxidation reaction is element (arsenic) As,as the Oxidation number is increased from +3 to +5.

As2O3 ______> H3AsO4

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