I am trying to find the specific optical rotation of my D-Limonene solution. I g

Question

I am trying to find the specific optical rotation of my D-Limonene solution. I got the observed optical rotation to be 14.33°. I am aware of the equation used to find the specific optical rotation. However, I am stuck on calculating the concentration. My TA told me to use the known density of Limonene to find the concentration of the solution. A 9 mL ethanol + 1 mL D-Limonene solution was used when doing the polarimetry experiments. This is what I did to find out the concentration of the solution:

Grams of solute = (0.841 g/mL)(1 mL D-Limonene) = 0.841 g D-Limonene

mL solvent = 9 mL ethanol

Concentration = grams of solute/mL of solvent = 0.841 g / 9 mL = 0.093 g/mL

If that is correct, to find the specific optical rotation, would I do 14.33°/(0.093)(1 dm)?

Explanation / Answer

You are right

observed rotation = 14.33

mass of solute = 0.841g/mlL x 1mL = 0.841g

Thus concentration of limonene = 0.841g/ 9mL

= 0.0934 g/mL

We know that specific rotation = observed rotation /(concentrationing/mL) (length in dm)

= 14.33/ (0.0934)(l dm)

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