Lithium oxide (Li2)) can be used to remove water from air. The balanced equation

Question

Lithium oxide (Li2)) can be used to remove water from air. The balanced equation for the reaction of lithium oxide with water is: Li2O(s) +H2O(g) --> 2 LiOH(s).

List the steps that you would have to follow to determine how many grams of water can be removed from the air by 250 g of Li2O, and identify the links between quantities. (Example: If you wanted to convert from umol of a substance to grams, the steps would be umol --> mol --> grams. The link between umol and mol would be 1 umol = 1E-6 mol, and the link between mol and grams would be the molar mass.)

Explanation / Answer

given reaction is

Li2O   + H2O ----> 2 LiOH

1mole 1mole      1mole

1 mole of water can be removed by one mole Li2O

molar mass of Li2O = 30 g/mol

molar mass of water = 18 g/mol

250 g of Li2O will contain = mass of Li2O / molar mass of Li2O number of moles

                                          = 250 g / 30 g/mol = 8.33 moles of Li2O

250 g of Li2O will contain 8.33 moles of Li2O

8.33 moles of Li2O can absorb 8.33 moles of water

mass of water = no. of moles of water * molar mass of water = 8.33 mol * 18 g/mol = 150 g of water

Answer

250 g of Li2O can absorb 150 g of water

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