Lithium nucleus affected by an electric field A proton at location A makes an el

Question

Lithium nucleus affected by an electric field A proton at location A makes an electric field E rightarrow_1 at location B. A different proton, placed at location B, experiences a force F rightaroow_1. If |E rightarrow_1| = 500 N/C, what is |F rightarrow_1|? Now the proton at B is removed and replaced by a lithium nucleus, containing three protons and four neutrons. The proton at location A remains in place. What is the magnitude of the electric force on the lithium nucleus? |F rightarrow_on Li| = N Now the Lithium nucleus is removed, and an electron is placed at location B. The proton at location A remains in place. What is the magnitude of the electric force on the electron? |F rightarrow_on e^-1 = N Which arrow below best indicates the direction of the force on the electron due to the electric field?

Explanation / Answer

for the force F1

F1 = 500 * 1.602 *10^-19

F1 = 8.01 *10^-17 N

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force on the Litium ion = E1 * charge

force on the Litium ion = 500 * 3 * 1.602 *10^-19

force on the Litium ion = 2.4 *10^-16 N

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force on the electron = electric field * charge

force on the electron = 500 * 1.602 *10^-19

the force on the electron is 8.01 *10^-17 N

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for the direction of electric field is f (towards the point A)

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