Ok, so my question here is do I have an exact product. The first picture is the

Question

Ok, so my question here is do I have an exact product. The first picture is the IR for the starting material and the second picture is the actual IR for my product. I see in the results that I do have an alcohol but did I loose the ketone from the starting material? The final product should be 4-tert-butlycyclohexanol in the cis and trans conformation. The starting material is listed on the original IR spectra. Thanks.

Infrared Spectra MICRONS H, CCCH, CH MELT 4600 4400 4200 4000 3800 3600 3400 3200 3000 2800 2600 2400 2200 2000 1800 WAVENUMBERS The following is the IR spectrum for 4-t-butylcyclohexanone. 2956.3 1420.1 1162.2 1719.6 1366.9 943.1 1479.6 1220.2 511.5 Los NICOLET 20SX FT

Explanation / Answer

Frequency range in cm-1 of O-H group is 3200-3600 (H-bonded) and 3500-3700 (free H-) and for C=O group it is 1670-1820 cm-1.

As it can be seen in first spectra,(of the starting material) there is a prominent peak for C=O group (at around 1710 cm-1) which implies presence of ketone. In the second spectra (of the product ), there is a peak for O-H group at 3288 cm-1 but there is no peak in the range of ketone (1670-1820 cm-1) thus ketone is lost from the starting material. This conversion is probably carried out by reducing ketone of starting material to alcohol in the product.

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