ew m Course: KON RNG (2017A mal tamu My eCampus ....board Learn saplng Learning

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ew m Course: KON RNG (2017A mal tamu My eCampus ....board Learn saplng Learning Chem MAX30-Max ...at on Vimeo 45 minutes of dea x Texas A&M; Unil CHEM 112 Lab Funda, score 2/6/2017 11:30 AM G 7.8/20 Time Remaining: 22 M 27 s B Gradebook Print Calculator Periodic Table Sapling Learning A .0000406 M sample of Compound has an or 0229 at 528 nm in a 100o cm 0. cuvet. The solvent alone has an absorbance of 0.055. What is the molar absorptivity of Compound X? M-1 cm different sample of Compound Xin the same has an 0.456 at 528 nm when measured with the same What is the concentration of this second sample? A Previous Check Answer Next Ext r

Explanation / Answer

Absorbance due to compound X = 0.229 - 0.055 = 0.174

molar absorptivity = absorbance/conc x path length

                             = 0.174/4.06 x 10^-5 x 1

                             = 4286 M-1.cm-1

A different sample of X,

concentration of [X] = absorbance/molar absorptivity

                                = (0.456 - 0.055)/4286

                                = 9.35 x 10^-5 mol X/L

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