ew History Bookmarks Develop Window Help WileyPLUS: I Contact Us 1 GENERAL PHYSI
ID: 1880110 • Letter: E
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ew History Bookmarks Develop Window Help WileyPLUS: I Contact Us 1 GENERAL PHYSICS (PHYS 2001/208 Cutnell, Physics, 1le Gredebook ORION Dewnloadable eTextbook Chapter 04, Problem 013 Your answer is partially cormect. Try again. a review of the concepts that are important in this problem A rocket of mass 4.09 x 103 kg is in flight near earth's surface. Its er ut i' aected at an angie U s2a. above the honontal and has a magrt de of 9.51 x 10e N. Find the (a) magnitude and (b) direction ofthe rocket's acceleration. Give the direction as an angle above the horizontal. (b) nor 898 2Explanation / Answer
Net force in y direction= Thrust in vertical direction - weight= 9.51x 10^6 sin52.6 - 4.09 x 10^5 (9.8) = 75.55 x 10^5 - 40.082 x 10^5 = 35.468 x 10^5 N
force in x direction= 9.51x 10^6 cos 52.6=57.76 x 10^ 5 N
resultant force= 10^5 sqroot ( 35.468 ^2 + 57.76^2) = 67.78 x 10^5 N
a= F/m = 67.78 x 10^5/4.09 x 10^5=16.57 m/s^2
angle = tan^-1 (Fy/Fx) = tan^-1 (35.468/57.76 )=31.55 degree apprx
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