You will be collecting a gas over water in this experiment. If the class baromet
ID: 478047 • Letter: Y
Question
You will be collecting a gas over water in this experiment. If the class barometer reports an atmospheric pressure of 29.86 in Hg, what is the pressure of the gas mixture collected above the water in units of mmHg? Remembering that the pressure of the gas integral the head space includes the vapor pressure of water, how would you determine the pressure of the collected dioxygen gas alone, assuming room is 25 degree C? Please describe function of a catalyst in a chemical reaction. What is the catalyst in this experiment? In this lab, only the solutions that contain lead are collected as hazardous waste. Please list at least two reasons lead nitrate is treated with caution in the lab. You might be interested in lead the safety data sheet () for lead nitrate.Explanation / Answer
1) Given that atmospheric pressure = 29.86 inHg = 29.86 inches of Hg
= 29.86 x 25.4 mmHg [ 1 inHg = 25.4 mmHg]
= 758.4 mmHg
Therefore,
Pressure of the gas mixture collected above the water = 758.4 mmHg
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Pressure of dioxygen alone = Pressure of the gas mixture - vapour pressure of water at 25oC
= 758.4 mmHg - 23.8 mmHg
= 734.6 mmHg
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