A clinical laboratory tested a new method for determining serum chloride ion con

Question

A clinical laboratory tested a new method for determining serum chloride ion concentration. The method gives the following results for a reference sample: 34.7, 35.6, 34.3, 35.9, and 35.0 mg/mL. Determine the precision of the method by calculating the standard deviation and the relative standard deviation.

2/6/2017 10:00 PM A 22.4150 O 1/28/2017 05:46 PM Gradebook Print calculator Periodic Table Question 14 of 29 Incorrect a Sapling Learning macmillan learning A clinical laboratory tested a new method for determining serum chloride ion concentration. The method gives the following results for a reference sample: 34.7, 35.6, 34.3, 35.9, and 35.0 mg/mL. Determine the precision of the method by calculating the standard deviation and the relative standard deviation. Number Incorrect. mg/ mL Standard deviation 0.583 The formula for the standard deviation is s n- 1 Number Relative standard deviation l 1.65 not Previous 3 Give Up & View Solution Try Again Next Exit

Explanation / Answer

The mean of the sample = (34.7+ 35.6+ 34.3+35.9+ 35.0)/5 =35.1 mg/mL.

Standard deviation =square root of [(34.7-35.1)^2+(35.6-35.1)^2+(34.3-35.1)^2+(35.9-35.1)^2+(35-35.1)^2]/(5-1)

=square root of(1.7)/4 =0.3259 mg/mL

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ralative deviation =100s/mean =(100*0.3259 mg/mL. )/35.1 mg/mL. =0.9284 %

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