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You want to react copper (I) chloride with iron metal. Do you expect the reactio

ID: 476354 • Letter: Y

Question

You want to react copper (I) chloride with iron metal. Do you expect the reaction to occur? No, because water or gas is not formed. Yes, because iron is less active than copper on the activity series. Yes, because iron is more active than copper on the activity series. No, because iron is more active than copper on the activity series. In order for a combustion reaction to occur, the reactant/s must include: an organic compound and oxygen an organic compound CO_2(g) and H_2O_(g) CO_2(g) and H_2O_(l) How many moles are present in 1.21 times 10^24 molecules of HBr? 7.28 moles 0.500 moles 2.01 moles 0.201 moles A 10.00g sample of a substance is found to contain 5.12g of water. What is the percent by mass of water in the compound? 5.12% 4.88% 48.8% 51.2% A 65.2 g sample of a compound contains 32.1 g of phosphorus and the rest is oxygen. What is the empirical formula of the compound ? P_2O_2 PO_2 PO P_2O_3 What is the molecular formula of a compound with the empirical formula CH and molar mass of 26.04g? CH C_2H CH_2 C_2H_2 A 6.00g sample of calcium sulfide is found to contain 3.33g of calcium. What is the percent by mass of sulfur in the compound? 80.2% 35.7% 44.5% 28.6% One atom of sulfur has a mass of 5.33 times 10^-23 g 32.06g 1.88 times 10^22 g 1.93 times 10^25 g What mass of H_2O is produced when 60.0g of CH_4 reacts completely in the following equation? CH_4 + 2O_2 rightarrow CO_2 + 2H_2O 2.41g 9.64g 33.7g 135g What is the percent yield in a reaction in which 1.038g of a product is actually produced when the theoretical yield is 1.132g? 8.304% 109.1% 89.16% 91.70% Calculate how much ethanol, C_2H_5OH, will be produced from the reaction of 590. g of sugar (C_6H_12O_6) if the reaction has a 88.5% yield.

Explanation / Answer

9) yes, because iron is more active in acitvity series than copper

10) an organic compound and oxygen

11) 2.01 moles of HBr if question is 1.21 * 1024             

No. of Moles = No. molecules / avagadro no. = 1.21 * 1023 /6.023 * 1024 = 2.01

12) mass % of water = (mass of water/total mass) * 100 % = (5.12/10) * 100 % = 51.2%

13) PO2

14) C2H2

15) 44.5 %

16) 32.06 g

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