The mass spectrum of an organic compound shows the relative abundances of M to b

Question

The mass spectrum of an organic compound shows the relative abundances of M to be 40.27% and M+1 to be 3.049%. Assuming the peaks are caused by 12C and 13C isotopes, determine the number of carbon atoms in the compound. Natural abundances: 12C is 98.93% and 13C is 1.07%

mass spectrum of an organic compound shows the relative abundances of M tube 4027N and sae caused by ec and ac isotopes, determine the number to be 3D49% Assuming the peak carbon atoms in the compound. Natural abundanoes: Be.s3s and sc is 107% carbo

Explanation / Answer

From the mass that, it is clear that the intensity of M peak is not 100% (only 40.27%). Hence, to get the number of carbon atoms, intensity of M+1 peak need to be recalculated with respect to M peak as:

M+1 = 3.049 x 100 / 40.27

M+1 = 304.9 / 40.27

M+1 = 7.57

Now, number of C atoms = 7.57 / 1.07

= 7.07 or

7 carbon atoms

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