A botanist studying waterlilies in an isolated pond observed three leaf shapes i

Question

A botanist studying waterlilies in an isolated pond observed three leaf shapes in the population: round, arrowhead, and scalloped. Marker analysis of DNAfrom 200 individuals showed the round-leafed plants to be homozygous for allele r1, while the plants with arrowhead leaves were homozygous for a different allele at the same locus. r2. Plants with scalloped leaves showed DNA profiles with both the r1 and r2 markers. Frequency of the r1 marker was estimated at 0.8.The botanist also counted 30 plants with scalloped leaves in the pond. What is the inbreeding coefficient F for this population? To calculate inbreeding coefficient from population data, use the following equation: F = (He-H0)/He where He is the number of heterozygotes expected in the population (determined by this calculation: 2pq x # of individuals in the population) and Ho is the number of heterozygotes observed in the population. Enter the value of F rounded to two decimal places. (Note: For your initial calculation of Hc , round that number to two decimal places.)

Explanation / Answer

Calculating He with the given formula: 2pq x number of individuals in the population.

We need to know the values of p and q.

Taking r1 as p and r2 as q:

since the frequency of r1 is given as 0.8, this indicates that the frequency of r2 is 0.2. [Since p+q =1]

Hence substituting in the formula:

He = 2 x 0.2 x 0.8 x 200

     = 64.

The number of heterozygotes observed H0 = 30

Now the inbreeding coefficient can be calculated:

F = (He - H0 ) / He

= (64 - 30)/30

= 1.13

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