Customers enter the camera department of a store at the average rate of three pe
ID: 449581 • Letter: C
Question
Customers enter the camera department of a store at the average rate of three per hour. The department is staffed by one employee, who takes an average of twelve minutes to serve each arrival. Assume this is a simple Poisson arrival exponentially distributed service time situation. Use Exhibit_7.12.
As a casual observer, how many people would you expect to see in the camera department (excluding the clerk)? (Round your answer to 2 decimal places.)
How long would a customer expect to spend in the camera department (total time)? (Round your answer to 1 decimal place.)
What is the probability that there are more than two people in the camera department (excluding the clerk)? (Round your answer to 4 decimal places.)
Another clerk has been hired for the camera department who also takes an average of twelve minutes to serve each arrival. How long would a customer expect to spend in the department now? (Round your answer to 3 decimal places.)
Customers enter the camera department of a store at the average rate of three per hour. The department is staffed by one employee, who takes an average of twelve minutes to serve each arrival. Assume this is a simple Poisson arrival exponentially distributed service time situation. Use Exhibit_7.12.
As a casual observer, how many people would you expect to see in the camera department (excluding the clerk)? (Round your answer to 2 decimal places.)
How long would a customer expect to spend in the camera department (total time)? (Round your answer to 1 decimal place.)
What is the probability that there are more than two people in the camera department (excluding the clerk)? (Round your answer to 4 decimal places.)
Another clerk has been hired for the camera department who also takes an average of twelve minutes to serve each arrival. How long would a customer expect to spend in the department now? (Round your answer to 3 decimal places.)
Explanation / Answer
The arrival rate A= 3 per Hour
The service rate S= 12minutes per customer means, in an hour 60/12 =5
1) The number of units in the system = A/(S-A) = 3/(5-3) = 3/2 = 1.5 Customers
2) The average time spend on the sytem = 1/(S-A) = 1/(5-3) = 1/2 hour = 30 minutes
3) The probability that more than two people in the department = (A/S)2 = (3/5)2 = 9/25
4) Now the service rate is S=10 per hour
The expected time to spend = 1/(S-A) = 1/(10-3) = 1/7 HOUR = 8.57 Minutes
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