You are the new process manager at a local manufacturer, and your first job is t

Question

You are the new process manager at a local manufacturer, and your first job is to inspect the quality of the end products. You conducted a 5-day data collection study to assess the quality of the products, and each day, you inspected 3,000 bottles. The company can produce a maximum of 450,000 bottles per day. The results are as follows Sample Day 1 Day 2 Day 3 Day 4 Day 5 # defected 80 120 201 155 102 Sample Size 3000 3000 3000 3000 3000 What are values of p-bar, Sp, UCL and LCL based on the results above.? Please use a confidence interval of 3 standard deviations

Explanation / Answer

p-bar = total no. of defects/total no. of observations

= (80+120+201+155+102)/(5*3000)

= 0.0439

Sp = standard deviation of pbar = [(p*(1-p))/n]^0.5

= [0.0439*(1-0.0439)/3000]^0.5

= 0.003739

UCL = p-bar+z*Sp

= 0.0439+3*0.003739

= 0.0551

LCL = p-bar - z*Sp

= 0.0439-3*0.003739

= 0.0326

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.